Reference To Local Variable Returned
Reference To Local Variable Returned. That means the returned reference is now dangling, and use of programname in the main() function results in undefined. How to return a local variable from a function?
The caller can then choose to treat the returned variable as if it were returned by value or by reference. So p would not be copied. A reference is an alias to an object.
Most Developers Are Familiar With Passing An Argument To A Called Method By Reference.
You can return a reference to ref/out parameters. And hence the value got displayed on screen by cout << number. If you have big structs, you can now reference these directly in safe code to avoid.
The Main Goal Of These New Features Is To Make It Easier For Developers To Pass Around References To Value Types Instead Of Copies Of Their Values.
It’s possible to return a reference from a function. There is a time and place for each, so make sure you get to know them. Returning a parent object has also the issue of object slicing;
That Means Local Variables Now Can Also Be Declared With The Ref Modifier.
The object that is returned by this function will bind to the reference and be returned to the caller. We should never return a local variable as a reference , reason being, as soon as the functions returns, local variable will be erased , however, we still will be left with a reference which might be a security bug in the code. A compiler is not required to generate a diagnostic either.
Visual Basic Does Not Suffer From The Same Issues.
Upon leaving a function, all local variables are destroyed. You would be better off in that case doing this. You should have that in account.
In Most Languages Local Variables Are Freed On Function Exit.
So the return of the function will be a reference to a (part of) local variable p. If this was done on purpose then i'm sorry for. You can not return a reference to this in structs.
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